Now that you have the idea of squaring numbers 'digit per digit' using SSQ, it is also an advantage if you can do things mentally or in short cuts.
In INTRODUCTION, I required you to remember the "index squares" of the single-digit numbers from 0 to 9. But this time, it will also be an "added advantage" if you can also memorize the squares of other numbers, to at least up to 15.( To be frank, I myself can only memorize the squares of numbers up to 15)
102 = 100 112 = 121 122 = 144 132 = 169 142 = 196 152 = 225
In my third article (Three-Digit Number Squaring), I introduced to you to the word "groupee" as the fun way of calling a group of digits considered as one unit. The above numbers from 10 up to 15 can be considered as groupees, They consist of two digits that act as one number. We can no longer say 11 as "one-one" but rather, as, "eleven", neither 10 as "one-zero" but rather as "ten".
In SSQ, there are instances (if you know the technique), that we can divide a multiple-digit number into groups of digits (groupees) as a "short way" of squaring numbers. To further understand what I'm talking about, it is important that I must first, show you an example
Question:
1242 = ?
There are two ways of getting the square value of 124
Digit Per Digit SSQ Approach
(Example 1)
1242 = (Blank)
12..2 = 01'04..
1x4 = 4 .
1242 = 01'44'16
" x 8 = 9'6 .
.............01'53'76
Groupee SSQ Approach
If you look closely at the given number 124, you may notice that it consist of a groupee (12) and a single digit 4. So, we can simplify our way of squaring that number by...
(Example 2)
1242 = 01'44'16
12x8 . 9'6 .
.............01'53'76
Groupee Index Squares
102 = 01'00
112 = 01'21
122 = 01'44
132 = 01'69
142 = 01'96
152 = 02'25
If you are gifted enough, that you can memorize the squares of numbers more than the listed numbers above, then it will be really an easy thing for you to do "groupee squaring"
(Example 3)
4122 = ?
If you will notice, the given number 412, is again, a combination of a single digit followed by a groupee...
4122 = 16'01'44
4x24 = . 96 .
.............16'97'44
Again, if you look at them closely, 124 and 412 are somehow, related, in a sense that we use the same index squares (16 and 01'44), except their positions are interchanged
Adjust SP Two Digits to The Left
4122 = 16'01'44 ← PSL
4x24 =. 96^^ ← SP ( you might notice that 6 of 96 is aligned to second 1 of 16'01'44)
.............16'97'44
It is very important that you 'be more careful' in aligning the sub-product to the PSL when doing 'groupee squaring'. Take note that in Example 2, the last digit is a single digit 4, so, we simply adjust the SP one digit to the left. While in Example 3, the last digit is not exactly the single digit 2 but the groupee '12', which happens to be a two-digit groupee. In that case, adjust the last digit of the SP, two digits to the left.
(Example 3)
1,4132 = ?
14132 = 01'96'01'69
14x26 = 3'64 .
...............01'99'65'69
Showing posts with label digit. Show all posts
Showing posts with label digit. Show all posts
Friday, November 1, 2013
Wednesday, October 30, 2013
E. Squaring Multiple-Digit Numbers
Four-Digit Number Squaring
Question: What is the square of 2,384?
2,3842 = ?
Following the rules we just learned...
2,3842 = (leave this space blank)
23..2 = 04’09.. ← PSL 1
+2x3x2= 1'2 . ← SP1 (2 of 12 is aligned to second 0 of 04'09)
238..2 = 05’29'64 ← PSL 2
23x16 = . 36'8 . ← SP 2 (8 of 36'8 is aligned to 6 of 05'29'64)
23842= 05'66'44'16 ← PSL 3 (new PSL)
" x 8 =. 1'90'4 . ← SP3 (new SP) (4 of 1'90'4 aligned to 1 of 05'66'44'16)
..............05'68'34'56 ← T-Sum
Write in the 'blank space' above 23..2 , the actual number value of 2,3842
2,3842 = 5,683,456
You might noticed that the same procedures are applied in squaring a multiple-digit number such as in the four-digit number 2384. The only difference is that as the digits increases, so do the way we do the SSQ method.
As a summary:
1) Do the two-digit squaring for first two digits 2 and 3.
2) The partial sum become part of the new PSL (PSL2) and we insert the next digit 8 along with its equivalent index square 64.
3) Add the SP2 to PSL2 to get the new partial sum.
4) The partial sum become part of another new PSL (PSL3) and we, again insert the next digit 4 along with its equivalent index square 16.
5) Add the new Sub-product (SP3) to the PSL3 to get the Total Sum (T-Sum)
The " Notation
You might also noticed that instead of writing, 238 x 8 at the left side of the SP3 line (look the yellow shade below), we simply indicated the " notation. We do that so that we can save time and effort in repeating to write numbers.Just makes it sure that you properly multiply the "all to the left" of the last digit, to the double value of the last digit itself ( remember Dou-LAL?)
23..2 = 04’09.. ← PSL 1
+2x3x2= 1'2 . ← SP1 (2 of 12 is aligned to second 0 of 04'09)
238..2 = 05’29'64 ← PSL 2
23x16 = . 36'8 . ← SP 2 (8 of 36'8 is aligned to 6 of 05'29'64)
23842= 05'66'44'16 ← PSL 3 (new PSL)
" x 8 =. 1'90'4 . ← SP3 (new SP) (4 of 1'90'4 aligned to 1 of 05'66'44'16)
..............05'68'34'56 ← T-Sum
Underlined Last Digit
You might also noticed that the 'involved' last digit is always 'underlined'. As a beginner, you are required to do this but as you become familiar with the method of Systematic Squaring (SSQ), there's no need to do this. Just make sure that you're doing the right thing.
23..2 = 04’09.. ← PSL 1
+2x3x2= 1'2 . ← SP1 (2 of 12 is aligned to second 0 of 04'09)
238..2 = 05’29'64 ← PSL 2
23x16 = . 36'8 . ← SP 2 (8 of 36'8 is aligned to 6 of 05'29'64)
23842= 05'66'44'16 ← PSL 3 (new PSL)
" x 8 =. 1'90'4 . ← SP3 (new SP) (4 of 1'90'4 aligned to 1 of 05'66'44'16)
..............05'68'34'56 ← T-Sum
Exercise: (Do It Yourself)
Now that you have the clear idea of how SSQ works, try to square the following given numbers:
1) 45,896
2) 398
3) 978,675
Question: What is the square of 2,384?
2,3842 = ?
Following the rules we just learned...
2,3842 = (leave this space blank)
23..2 = 04’09.. ← PSL 1
+2x3x2= 1'2 . ← SP1 (2 of 12 is aligned to second 0 of 04'09)
238..2 = 05’29'64 ← PSL 2
23x16 = . 36'8 . ← SP 2 (8 of 36'8 is aligned to 6 of 05'29'64)
23842= 05'66'44'16 ← PSL 3 (new PSL)
" x 8 =. 1'90'4 . ← SP3 (new SP) (4 of 1'90'4 aligned to 1 of 05'66'44'16)
..............05'68'34'56 ← T-Sum
Write in the 'blank space' above 23..2 , the actual number value of 2,3842
2,3842 = 5,683,456
You might noticed that the same procedures are applied in squaring a multiple-digit number such as in the four-digit number 2384. The only difference is that as the digits increases, so do the way we do the SSQ method.
As a summary:
1) Do the two-digit squaring for first two digits 2 and 3.
2) The partial sum become part of the new PSL (PSL2) and we insert the next digit 8 along with its equivalent index square 64.
3) Add the SP2 to PSL2 to get the new partial sum.
4) The partial sum become part of another new PSL (PSL3) and we, again insert the next digit 4 along with its equivalent index square 16.
5) Add the new Sub-product (SP3) to the PSL3 to get the Total Sum (T-Sum)
The " Notation
You might also noticed that instead of writing, 238 x 8 at the left side of the SP3 line (look the yellow shade below), we simply indicated the " notation. We do that so that we can save time and effort in repeating to write numbers.Just makes it sure that you properly multiply the "all to the left" of the last digit, to the double value of the last digit itself ( remember Dou-LAL?)
23..2 = 04’09.. ← PSL 1
+2x3x2= 1'2 . ← SP1 (2 of 12 is aligned to second 0 of 04'09)
238..2 = 05’29'64 ← PSL 2
23x16 = . 36'8 . ← SP 2 (8 of 36'8 is aligned to 6 of 05'29'64)
23842= 05'66'44'16 ← PSL 3 (new PSL)
" x 8 =. 1'90'4 . ← SP3 (new SP) (4 of 1'90'4 aligned to 1 of 05'66'44'16)
..............05'68'34'56 ← T-Sum
Underlined Last Digit
You might also noticed that the 'involved' last digit is always 'underlined'. As a beginner, you are required to do this but as you become familiar with the method of Systematic Squaring (SSQ), there's no need to do this. Just make sure that you're doing the right thing.
23..2 = 04’09.. ← PSL 1
+2x3x2= 1'2 . ← SP1 (2 of 12 is aligned to second 0 of 04'09)
238..2 = 05’29'64 ← PSL 2
23x16 = . 36'8 . ← SP 2 (8 of 36'8 is aligned to 6 of 05'29'64)
23842= 05'66'44'16 ← PSL 3 (new PSL)
" x 8 =. 1'90'4 . ← SP3 (new SP) (4 of 1'90'4 aligned to 1 of 05'66'44'16)
..............05'68'34'56 ← T-Sum
Exercise: (Do It Yourself)
Now that you have the clear idea of how SSQ works, try to square the following given numbers:
1) 45,896
2) 398
3) 978,675
Sunday, October 27, 2013
C. Squaring Three-Digit Numbers
Squaring a three-digit number using SSQ is as simple as squaring a "two-digit" number. It is my advise that you must first read my first two articles (entitled, "Introduction" and "Squaring Two Digit Numbers") to fully appreciate how SSQ works for three-digit numbers.
Question: What is the square of 238?
Question: What is the square of 238?
2382 = ?
General Rule:
In squaring number using SSQ, no matter how many digits it has (or involved) - you must always 'remember' that it is much easier to deal it by 'doing things' two separate digits at a time.
238 is a three-digit number. By general rule, we must deal (or consider) 238 as three separate digits as 2 - 3 - 8.
Now, focus your attention on the first two separate digits 2 and 3...
23..2 = (leave this space blank)
23..2 = 04’09.. ← PSL
+2x3x2 = 1'2 . ← SP1 (2 of 12 is aligned to second 0 of 04'09)
................05’29.. ←Partial Sum (remember, this is not yet the final answer)
You might notice that the above computation is the same as to the example given on Squaring Two-Digit Numbers.
Groupee
What we actually done is the same process or procedure as we learned in squaring two-digit number. Now, in this case, there is a remaining digit 8, in the given value 238 that we must deal with.
At the moment, don't bother yourself about that remaining digit. Let's first consider the square of 23.
23..2 = 05'29..
In reality, 05'29 is the 'actual square' of 23. But in SSQ, as fun way of memorizing words, let's call 05'29 as the square of the 'groupee' 23.
Groupee, is a group of digits considered as one unit. 2 and 3 as separate digits in the first procedure that we had done (Two-Digit SSQ)., will now be a groupee known as 23.
Its corresponding 'square' will then become part of the new PSL (Partial Square Line) along with a new 'index square' of the remaining digit 8.
2382 = 05'29'64
Now, as a general rule of SSQ, we must get the sub-product (new SP), using the DouLAL Multiplication Pattern
Activity 1: "DouL" means Double the Last digit...
8 x 2 = 16
Activity 2: "AL" means Multiply to All in Its Left
You may notice that the 'all to the left' of 8 is 23 in the given value 238, so...
23 x 16 = 368
The last procedure will then be, add the new sub-product (SP) to the new Partial Square Line (PSL) to get the T-Sum.
2382 = 05'29'64 ← new PSL
23x16 = 36'8 . ← new SP1
............05'66'44 ← T-Sum
Practical Technique for Three-Digit SSQ
Step 1: Consider squaring the first two digits using SSQ method..
2382 = (leave this space blank)
23..2 = 04’09.. ← PSL
+2x3x2 = 1'2 . ← SP1 (2 of 12 is aligned to second 0 of 04'09)
................05’29.. ←Partial Sum
Step 2: Create a new PSL
Activity 1: To conserve time and effort (as well as your ball pen's ink), write down at the left side of the partial sum, 23 along with the third digit 8 and underline 8. Don't forget the square sign ( _ 2 ).
Activity 2: At the right of the partial sum, write down the index square for 8.
2382 = (leave this space blank)
23..2 = 04’09.. ← PSL 1
+2x3x2 = 1'2 . ← SP1 (2 of 12 is aligned to second 0 of 04'09)
2382 = 05’29'64 ← PSL 2 (the new PSL)
Step 3: Find the new Sub-product. Add it to the new PSL to get the T-Sum.
2382 = (leave this space blank)
23..2 = 04’09.. ← PSL 1
+2x3x2 = 1'2 . ← SP1 (2 of 12 is aligned to second 0 of 04'09)
2382 = 05’29'64 ← PSL 2 (the new PSL)
23x16 = . 36'8 . ← SP 2 (the new SP)
............. 05'66'44 ← T-Sum
Step 4: As the final step, write down the actual value of T-Sum.
Remember that we left blank the space after we wrote down 2382
Now, we can use this space to write down the 'actual value' of 05'66'44
2382 = 56, 644 ← "Final Answer"
23..2 = 04’09.. ← PSL 1
+2x3x2 = 1'2 . ← SP1 (2 of 12 is aligned to second 0 of 04'09)
2382 = 05’29'64 ← PSL 2 (the new PSL)
23x16 = . 36'8 . ← SP 2 (the new SP)
............. 05'66'44 ← T-Sum
"Double Dots" Sign
Maybe, you noticed that there are those 'double dots' after 23 in 23..2 and also after 04'09 in 04’09.. . We simply use this sign to indicate that there is a following digit or digits after 23.
As part of the rule, make it as a practice to include the 'double dots' in performing SSQ.
Now, it's time to level-up. You are now ready to do the squaring of numbers in more than three digits. Next topic, the multiple-digit squaring, enjoy it.
General Rule:
In squaring number using SSQ, no matter how many digits it has (or involved) - you must always 'remember' that it is much easier to deal it by 'doing things' two separate digits at a time.
238 is a three-digit number. By general rule, we must deal (or consider) 238 as three separate digits as 2 - 3 - 8.
Now, focus your attention on the first two separate digits 2 and 3...
23..2 = (leave this space blank)
23..2 = 04’09.. ← PSL
+2x3x2 = 1'2 . ← SP1 (2 of 12 is aligned to second 0 of 04'09)
................05’29.. ←Partial Sum (remember, this is not yet the final answer)
You might notice that the above computation is the same as to the example given on Squaring Two-Digit Numbers.
Groupee
What we actually done is the same process or procedure as we learned in squaring two-digit number. Now, in this case, there is a remaining digit 8, in the given value 238 that we must deal with.
At the moment, don't bother yourself about that remaining digit. Let's first consider the square of 23.
23..2 = 05'29..
In reality, 05'29 is the 'actual square' of 23. But in SSQ, as fun way of memorizing words, let's call 05'29 as the square of the 'groupee' 23.
Groupee, is a group of digits considered as one unit. 2 and 3 as separate digits in the first procedure that we had done (Two-Digit SSQ)., will now be a groupee known as 23.
Its corresponding 'square' will then become part of the new PSL (Partial Square Line) along with a new 'index square' of the remaining digit 8.
2382 = 05'29'64
Now, as a general rule of SSQ, we must get the sub-product (new SP), using the DouLAL Multiplication Pattern
Activity 1: "DouL" means Double the Last digit...
8 x 2 = 16
Activity 2: "AL" means Multiply to All in Its Left
You may notice that the 'all to the left' of 8 is 23 in the given value 238, so...
23 x 16 = 368
The last procedure will then be, add the new sub-product (SP) to the new Partial Square Line (PSL) to get the T-Sum.
2382 = 05'29'64 ← new PSL
23x16 = 36'8 . ← new SP1
............05'66'44 ← T-Sum
Practical Technique for Three-Digit SSQ
Step 1: Consider squaring the first two digits using SSQ method..
2382 = (leave this space blank)
23..2 = 04’09.. ← PSL
+2x3x2 = 1'2 . ← SP1 (2 of 12 is aligned to second 0 of 04'09)
................05’29.. ←Partial Sum
Step 2: Create a new PSL
Activity 1: To conserve time and effort (as well as your ball pen's ink), write down at the left side of the partial sum, 23 along with the third digit 8 and underline 8. Don't forget the square sign ( _ 2 ).
Activity 2: At the right of the partial sum, write down the index square for 8.
2382 = (leave this space blank)
23..2 = 04’09.. ← PSL 1
+2x3x2 = 1'2 . ← SP1 (2 of 12 is aligned to second 0 of 04'09)
2382 = 05’29'64 ← PSL 2 (the new PSL)
Step 3: Find the new Sub-product. Add it to the new PSL to get the T-Sum.
2382 = (leave this space blank)
23..2 = 04’09.. ← PSL 1
+2x3x2 = 1'2 . ← SP1 (2 of 12 is aligned to second 0 of 04'09)
2382 = 05’29'64 ← PSL 2 (the new PSL)
23x16 = . 36'8 . ← SP 2 (the new SP)
............. 05'66'44 ← T-Sum
Step 4: As the final step, write down the actual value of T-Sum.
Remember that we left blank the space after we wrote down 2382
Now, we can use this space to write down the 'actual value' of 05'66'44
2382 = 56, 644 ← "Final Answer"
23..2 = 04’09.. ← PSL 1
+2x3x2 = 1'2 . ← SP1 (2 of 12 is aligned to second 0 of 04'09)
2382 = 05’29'64 ← PSL 2 (the new PSL)
23x16 = . 36'8 . ← SP 2 (the new SP)
............. 05'66'44 ← T-Sum
"Double Dots" Sign
Maybe, you noticed that there are those 'double dots' after 23 in 23..2 and also after 04'09 in 04’09.. . We simply use this sign to indicate that there is a following digit or digits after 23.
As part of the rule, make it as a practice to include the 'double dots' in performing SSQ.
Now, it's time to level-up. You are now ready to do the squaring of numbers in more than three digits. Next topic, the multiple-digit squaring, enjoy it.
Saturday, October 26, 2013
B. Squaring Two-Digit Numbers
Common Way of Multiplying Numbers
Squaring a number is the same as multiplying two numbers having identical values.
Example:
Square the number 743 = 743x 743.
1) Multiply 743 by 3. Put the carries above 743 and the partial product = 2229
2) Then multiply 743 by 4. The partial product = 2972. Put the last digit 2 on the tens decimal place.
3) Lastly, multiply 743 by 7. the partial product = 5201. Put the last digit 1 on the hundreds decimal place.
4) Add the partial products and what we get is = 552049 or 552,049
That is how we commonly get the square of a number.
Systematic Squaring Method (SSQ)
This time, I’ll teach a new way of getting the squares of numbers in an easier and orderly manner. But first, you must also know some new things.
Digit Number
A digit (what I’m talking about here is the numeric digit), is either any of the following;
0, 1, 2, 3, 4, 5, 6, 7, 8 or 9
A number such as 743 has three digits, 7, 4 and 3. Sometimes it is called a three-digit number. All you have to do is to count the digits. Counting the digits of 4,569,742, we can then, name that number, as a seven-digit number. In SSQ, the “count of digits of a number is important”.
Later, you will realize the reason why it is important. But for now,
giving you the idea of what a digit of a number is all about, would be
enough.
Meaning of SSQ
SSQ stands for Systematic Squaring. It is based on a popular algebraic equation, (X + Y)2. It is much different from the common method of multiplying two identical numbers.
SSQ has only three main parts, namely:
1) PSL (Partial Squares Line)
2) Sub-product
3) Total Sum (TSum)
Index Squares
Always remember that there are only ten basic digits (numeric digits) and these are;
0, 1, 2, 3, 4, 5, 6, 7, 8 and 9
An index square is a product of a ‘basic digit’ multiplied by itself:
0x0 = 0 / 1x1 = 1 / 2x2 = 4 / 3x3 = 9 / 4x4 = 16
5x5 = 25 / 6x6 = 36 / 7x7 = 49 / 8x8 = 64 / 9x9 = 81
It is safe to call 0, 1, 4, 9, 16, 25, 36 , 49, 64 and 81 as index squares but in SSQ, an index square must be expressed as “two-digit square”. So the proper way of writing them are as follows:
Table of Index Squares
02 = 00
12 = 01
22 = 04
32 = 09
42 = 16
52 = 25
62 = 36
72 = 49
82 = 64
92 = 81
Two-Digit SSQ
Let's start by squaring a two-digit number, using the SSQ method
Question: What is the square of 23?
232 = ?
Step 1: Create a PSL
Partial Squares Line (PSL)
The PSL is simply, the “two-digit squares” representation of each, individual digits of a certain number. In 232, the two-digit squares representation of the digits, 2 and 3 are 04 and 09, respectively. So we simply write it this way:
232 = 04’09 ← PSL
But
don’t forget to also include this sign - ’ (a special character called
single close quote). It will easily give us a clue of how many index
squares are there in a PSL.
Step 2: Solve the sub-product
Sub-Product (SP)
Don’t
think that the value we’d taken from the PSL is already the correct
answer. The value 04’09 is still incomplete. We must add a sub-product
to come up with the ‘true’ square value of 23. But to get the
sub-product of 23, we must multiply the digits 2 and 3 in a special kind of pattern.
General Rules in Dealing with the Sub-product
Rule 1: Look for the last digit of the given number
Rule 2: Double its value, meaning, multiply it by 2
Rule 3: Then multiply that value to the remaining digits on its left.
DOU-LAL Multiplication Pattern
Dou-LAL stands for "Double the Last Digit and All to It's Left". It is simply an easy to memorize acronym which is kind of multiplication pattern that is, effective in getting the sub-product. How it works?
HOW DOU-LAL WORKS?
In the given number 23, you may notice that 3 is the last digit, and on the left of 3 is 2.
Activity 1: Simply double the value of the last digit (which in this case, is 3)
3 x 2 = 6
Activity 2: Now, the "all to the left" of the last digit is in this case, is a single digit which is 2.
The next thing to do is to multiply 2 by 6, which happens to be the 'double value of the last digit' 3 of the given value 23
2 x 6 = 12
Officially, 12 will be the value of our Sub-product
Step 3: Find the 'total sum' by simply adding the Sub-product to the PSL with some little adjustment needed to perform.
Adjust SP One Digit to The Left
In strict ruling in Math, the sub-product of 23 should be:
20 x ( 2 x 3) = 120
But it is a 'short cut' way of writing number (for the value of SP in a two-digit squaring), if we try to omit the zero at the end of the SP
Instead of 120, we should simply write 12, by which the last digit of SP, must be aligned to the next digit to the left of the last digit of the PSL.
2 x 6 = 12
Officially, 12 will be the value of our Sub-product
Step 3: Find the 'total sum' by simply adding the Sub-product to the PSL with some little adjustment needed to perform.
Adjust SP One Digit to The Left
In strict ruling in Math, the sub-product of 23 should be:
20 x ( 2 x 3) = 120
But it is a 'short cut' way of writing number (for the value of SP in a two-digit squaring), if we try to omit the zero at the end of the SP
Instead of 120, we should simply write 12, by which the last digit of SP, must be aligned to the next digit to the left of the last digit of the PSL.
232 = 04’09 ← PSL
+2x3x2 = 1'2 ← SP1 (2 of 12 is aligned to second 0 of 04'09)
................05’29 ← T-Sum
Total Sum
In the above example, the value 05'29 will be our T-Sum, which is simply the result of adding the SP to the PSL. T-Sum reflects the true value of 232 or the square value of 23.
But in 'reality', we can't simply say that the square of 23 is 05'29. Instead, we must omit the zero (0) before the 5 and erase the ' ( single close quote).
So, the final answer will be:
232 = 529
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